Ok, you can start with the rows and columns with the smallest sum of filled spaces, which is 1 in this case.

Observe the row with 1 on the left, there are three thermometers in that row which has more than 1 space within that same row. Those are (delta), (gamma) and (epsilon), and only the bulb part of those thermometers can possibly be filled. So you can mark the remaining parts of those three thermometers as red or ‘0’. This way you remove the cells which will never be filled.

Similarly do the same for the column with 1 on the top, you can see towards the bottom of that column, only one thermometer (gamma) that came from a nearby column and it has more than 1 cell within that column. You can mark the tail part of that thermometer as red or ‘0’.

Do the same for the rows with 3 as the sum.

Mark green or ‘1’ where you know a cell of a thermometer will definitely be filled. And hence, starting from that point to the bulb will definitely be filled.

Then the cells where a thermometer has bent are also crucial. By using the above strategy, you can determine which part of a bent thermometer will be filled or unfilled.

This way, gradually you will progress towards the solution.